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I need help with a physics problem! (+REP FOR HELP!)
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I need help with a physics problem! (+REP FOR HELP!)Posted:
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I'll +rep you a whoooooooole lot if you can help me out here, guys. I can't figure this physics problem out.
A ball rolls off a horizontal table at 0.42m/s and strikes the ground 0.17m horizontally from the base of the table.
1) How high is the table?
2) If another ball rolls off the same table at 0.65m/s , how far from the base of the table does it hit?
A ball rolls off a horizontal table at 0.42m/s and strikes the ground 0.17m horizontally from the base of the table.
1) How high is the table?
2) If another ball rolls off the same table at 0.65m/s , how far from the base of the table does it hit?
#2. Posted:
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You wont be learning anything from us doing your homework for you
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#3. Posted:
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I'm going to give this a go but keep in mind I haven't done anything like this in a long time so I am probably wrong.
Velocity = 0.42m/s
Fall = 0.17m
t = d/s
t = 0.17 / 0.42
t = 0.4 seconds.
It took the ball 0.4 seconds to hit the ground, therefore.
h = 1/2gt^2
h = 1/2(9.80665)(0.4 ^2)
0.784532 = 1/2(9.80665)(0.4 ^2)
Height of the table = 0.78m.
2) t = square root of 2h / g
t = square root of 2(0.78) / 9.80665
t = 0.4 seconds, same time.
distance = speed * time
d = 0.65 * 0.4
Distance = 0.25m
1) The table is 0.78 meters high.
2) The ball falls 0.25 meters from the base of the table.
Velocity = 0.42m/s
Fall = 0.17m
t = d/s
t = 0.17 / 0.42
t = 0.4 seconds.
It took the ball 0.4 seconds to hit the ground, therefore.
h = 1/2gt^2
h = 1/2(9.80665)(0.4 ^2)
0.784532 = 1/2(9.80665)(0.4 ^2)
Height of the table = 0.78m.
2) t = square root of 2h / g
t = square root of 2(0.78) / 9.80665
t = 0.4 seconds, same time.
distance = speed * time
d = 0.65 * 0.4
Distance = 0.25m
1) The table is 0.78 meters high.
2) The ball falls 0.25 meters from the base of the table.
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#4. Posted:
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Try youtube videos they are great and helpful.
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#5. Posted:
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Just look for the equations, it's not that hard.
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#6. Posted:
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Just apply the Suvat equations in the x/y directions as appropriate, Boar's solution looks decent but I haven't worked through it myself personally. Try not to look at his answers until you have tried the problem yourself.
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